Linear Thermal Expansion Problems And Solutions Pdf Apr 2026

This article serves as a preview to that guide. Below, we explain the core formula, walk through three common types of problems, and tell you how to download a comprehensive PDF with 20+ solved problems. The change in length of a solid due to a temperature change is given by:

✅ Key takeaway: Expansion is small but critical in precision work. Question: A metal bar is 1.500 m at 15°C and 1.504 m at 85°C. Find α. linear thermal expansion problems and solutions pdf

ΔT = 30°C Strain if free = α ΔT = (2.3e-5)(30) = 6.9e-4 But walls prevent expansion → compressive stress: Stress = Y × (α ΔT) = (7.0e10)(6.9e-4) = 4.83 × 10⁷ Pa This article serves as a preview to that guide

ΔT = 60.0 – 20.0 = 40.0°C ΔL = (1.2 × 10⁻⁵)(2.000)(40.0) = 9.6 × 10⁻⁴ m = 0.00096 m Final length = 2.000 + 0.00096 = 2.00096 m Question: A metal bar is 1

✅ Compare to known values: This is likely aluminum or brass. Question: An aluminum rod (α = 2.3 × 10⁻⁵ /°C, Y = 7.0 × 10¹⁰ Pa) is 1.000 m at 20°C. It is fixed between two rigid walls. If the temperature rises to 50°C, what is the thermal stress?

ΔL = 1.504 – 1.500 = 0.004 m ΔT = 85 – 15 = 70°C α = ΔL / (L₀ ΔT) = 0.004 / (1.500 × 70) = 3.81 × 10⁻⁵ /°C